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skyhighozzie
02.10.2019 •
Physics
You drive in a straight line at 20.0 m/s for 10.0 min, then at 34.0 m/s for another 10.0 min. what is the average speed?
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Ответ:
Total distance = v1 * t1 + v2*t2= 20m/s * 10 min * 60 sec/min + 34 m/s * 10 min * 60 sec/min= 12000m+20400m= 32400m.
Then you need to divide the distance with the total time to find the average speed.
It would be: 32400m/ (10min+10min)= 32400m/20min * 1 min/60sec= 27m/s
Ответ:
The average speed when I drive in a straight line at 20.0 m/s for 10.0 min, then at 34.0 m/s for another 10.0 min is 27 m/s
Average speed: Thes can be defined as the ratio of the total distance to the total time traveled by a body.
The question above can be solved using the formula below
S = D/T Equation 1
Where S = Average speed, D = Total distance, T = total time
For the first case,
d₁ = s₁×t₁
Given: s₁ = 20 m/s, t₁ = 10 min = 10×60 = 600 s
d₁ = 20(600)
d₁ = 12000 m.
For the second case,
d₂ = s₂×t₂ Equation 2
Given: s₂ = 34 m/s, t₂ = 10 min. = 600 s
d₂ = 34(600)
d₂ = 20400 m
Therefore,
Total distance (D) = 12000+20400
D = 32400 m
Total distance (T) = 600+600 = 1200 s
S = 32400/1200
S = 27 m/s
Hence, What is the average speed is 27 m/s
Learn more about average speed here: link
Ответ:
YAYAYAYYAy
Explanation:
because