Physics: You get in your sailboat and leave the harbor, sailing at 40 degrees south of east for 22 km until you reach a buoy. you circle the buoy and then sail until you are 15 km directly to the north of the point where you first exited the harbor. a) how far have you travelled from the buoy? at what angle relative to south should you look in order to see the buoy?

Recessive, dominant Explanation:umm thats the answer...

You get in your sailboat and leave the harbor, sailing

elainnysanchez1541

05.01.2022

33.66 km

Explanation:

Given

First sailboat travel $40^{\circ}$ south of east for 22 km to reach the buoy

Position vector of buoy r_1

$r_1=22cos40\hat{i}-22sin40\hat{j}$

Final Position of sailboat r_3

$r_3=15\hat{j}$

from Figure we can say that

r_1+r_2=r_3

r_2=r_3-r_1

$r_2=15\hat{j}-22cos40\hat{i}+22sin40\hat{j}$

$r_2=-22cos40\hat{i}+29.14\hat{j}$

|r_2|=33.66 km

After reaching r_3

$tan\theta =\frac{22cos40}{29.14}$

$tan\theta =\frac{16.85}{29.14}$

$\theta =30.04^{\circ}east\ of\ south$

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