OnlyaBurden
27.11.2019 •
Physics
Your grandfather clock's pendulum has a length of 0.9930 m. part a if the clock runs slow and loses 19 s per day, how should you adjust the length of the pendulum? note: due to the precise nature of this problem you must treat the constant g as unknown (that is, do not assume it is equal to exactly 9.80 m/s2).
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Ответ:
Explanation:
The period (T) of a simple pendulum depends on the length (l) of the pendulum and acceleration due to gravity (g). The period of a simple pendulum can be calculated as follows:
T= 2
The number of hours in a day is 24 h.
Convert 24 h to second as follows,
24 x 60 x 60 =86400 s
The number of cycle’s clock made per day is,
86400/2 = 43200
If the clock runs, slow of 19 s, then there is 9.5 cycles is reduces per day. So,
( 43200 -9.5) cycles = 43190.5 cycles
The period would be reduces by. 43190.5/43200 = 0.9998
Then the new time period is,
T new = 0.9998 Told
Substitute
LNEW/LODD =
LNEW/LODD =0.9996
Substitute 0.9930 m for LODD
LNEW = 0.9930 X 0.9996 = 0.9926
The difference in the lengths is,
LNEW- LODD
= 0.9926- 0.9930 = -0.0004
This is the same as 0.4mm
Therefore, the new length of the pendulum is 0.9926m, the length of the pendulum should be reduced by. 0.4mm
Ответ: