Please help with this social question ❤️❤️❤️❤️

I can't see the question girly

The confidence interval is (0.616, 0.686).

To find the confidence interval, we first find p, the proportion of students:
658/1010 = 0.6515

The confidence interval follows the formula


To find the z-score associated with this level of confidence:
Convert 98% to a decimal:  98% = 98/100 = 0.98
Subtract from 1:  1-0.98 = 0.02
Divide by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this is closer to the z-score 2.33.  

Using our information, we have:


This gives us the interval (0.6515-0.0349, 0.6515+0.0349) or (0.616, 0.686).