En dirección hacia el sur, un tren viaja inicialmente a 16 m/s; si recibe una aceleración constante de 2 m/s2. ¿Qué tan lejos llegará al cabo de 20 s? ¿Cuál será su velocidad final en el mismo tiempo? *

la velocidad del tren es 56 m/s

Explanation:

Velocidad inicial del tren u = 16 m/s

aceleración del tren a = 2 m/s^2

intervalo de tiempo t = 20 s

velocidad final del tren v =?

Aplicando la primera ley de movimiento de Newton,

v = u + at

sustituyendo los valores en la ecuación, tenemos

v = 16 + (2 x 20)

v = 16 + 40

velocidad final de la lluvia = 56 m/s

Explanation:

The reaction in question is as follows ;

2H2 + O2  -> 2H2O

from the reaction, 2 moles of hydrogen react with 1 mole of O2 to give 2 moles of water.given the flow rate of hydrogen =  27 gmol/min gmol is defined = mass in grams / molecular weightmolecular weight of H2 = 2mass of hydrogen = 27 gmol x 2 = 54 g of H2 flows /minfrom the reaction ; 2moles of H2 react with 1 mole of O2, then the number of moles of O2 that will be needed to react with 27moles of Hydrogen will be 13.5moles which implies the amount of oxygen that needs to flow. As such, the amount of oxygen is 50% more than needed, this makes oxygen the excess reactants.As the amount needed is 13.5 moles which is 50% more =  13.5 x 50/100 = 6.75 moles. Therefore, total moles = 13.5 + 6.75 = 20.25 moles

Since the oxygen comes from air which has a component of 21 mole % oxygen and 79 mole% N2. it shows that since we have 20.25 moles of oxygen, then 76.17 moles of nitrogen also will be required.

Given that the conversion of H2 is 85% , hence the remaining hydrogen is unburnt which is 0.15 x 27 moles = 4.05 moles of hydrogen remaining. Amount of hydrogen burning is 0.85 x 27 = 22.95 molesThis will consume 22.95/2 = 11.475 moles of oxygen so the amount of O2 unreacted will be =  20.25 - 11.475 = 8.775 moles of oxygen.from the reaction, since 2moles of H2 produce 2moles of water, hence  22.95 moles of hydrogen that is burning it will also produce 22.95 moles of water.

Therefore, the flow rate of each of the specie will be ;

8.775 gmol/min of oxygen,22.95 g mol/min of water,4.05 gmol/min of hydrogen,76.17 gmol/min of nitrogen.