A biologist collected 50 liters of pond water and counted 10 mosquito larvae. How many larvae would you estimate to be in that pond if the total volume of water in the pond was 80,000 liters?
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Ответ:
The correct answer is - 16000 mosquito larvae.
Explanation:
Given:
Larvae per 50 liters = 10 mosquito larvae
The total volume of water in the pond = 80000 liters
Solution:
Numbers of larvae in 80000 liters of water
= 80000*10/50
= 1600*10
= 16000
Thus, the correct answer would be 16000 mosquito larvae
Ответ:
The stages of Meiosis 1 are,
(a) Prophase (which is sub-divided into 5 more stages which are Leptotene, Zygotene, Pachytene, Diplotene and Diakinesis)
(b) Metaphase,
(c) Anaphase,
(d) Telophase.
The Stages of Meiosis 2 are, Prophase, Metaphase, Telophase and Anaphase which are same as mitosis.
3. In meiosis, Cell divides twice.
4. In meiosis, 4 daughter cells are produced.
5. Yes, the chromosomal number in mitosis is reduced to half than normal i.e. 23
6. In meiosis, the final result is 4 haploid cells. If meiosis occurs in male then these haploid cells will be called sperms, if it occurs in female then they are called Ova(egg).
_____________________________________Just to give you some insight knowledge of Meiosis Im adding some extra points
Meiosis is a special type of cell division, which occurs only in the germ cells during the process of development and maturation to form gametes. It consists of two successive cell divisions,
Meiosis 1 : First meiotic division, that reduces the NUMBER of chromosomes i.e. the parent cell is diploid(46 Chromosomes) and the daughter cells are haploid(23 Chromosome). It also causes genetic variation in the haploid by cross linkage.
Meiosis 2 : Second meiotic division (Meiosis II) starts with two haploid parent cells and ends with four haploid daughter cells. Meiosis 2 like Meiosis 1, does not reduce the NUMBER OF CHROMOSOME that means the forming 4 daughter cells are haploid and their number of chromosome remains the same as the parent. BUT Haploid cells that go into the meiosis 2 have MORE AMOUNT OF CHROMOSOME THAN USUAL, thus MEIOSIS 2 REDUCES the amount of chromosome rather than the number of chromosome.
The DNA of the primitive germs cells is replicated prior to the meiosis 1 only and there is no replication of DNA before Meiosis 2. The four final cells reulting from the two meiotic divisions are not only haploid(i.e. containing 23 chromosome) but they are also containing 1n amount of DNA so that when the gametes fuse together forming a zygote, both the amount and number of chromosome and DNA remains SAME.
_____________________________________Meiosis is essential for the sexual reproduction of eukaryotic organisms because it enables genetic diversity through recombination, and the repair of genetic defects.
It contributes in genetic reassorment which ensures the genetic diversity in the offsprings. The genetic reassortment takes place by following two mechanisms:
During the prophase of meiosis 1, crossing over of genetic material between the homologous maternal and paternal chromosomes takes place which causes exchange of DNA fragments between the chromosome resulting is genetic diversity. During the anaphase of the first meiotic division, there is random distribution of maternal and paternal homologous chromosomes among the daughter cells which are produced as a result of meiotic division._____________________________________Best Regards,'Borz'