krisbiddulph1580
14.06.2020 •
Biology
A man who has male pattern baldness (X^bY) marries a woman who does not carry the allele (X^BX^B). What genotypic ratios would be expected of their children?
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Ответ:
2:2
Explanation:
The genotypic ratio of expected of their offspring would be 2:2.
From the illustration, the genotype of the man with male pattern baldness is while the genotype of the woman without the baldness allele is .
Crossing the two genotypes in marriage:
x
Progeny:
Hence, the genotypic ratio of the offspring becomes:
2:2
Ответ: