A. What happens to volume when a gas is heated in a container that can change size? B. What happens to the distance between the particles of a gas when it is heated?

(Temperature is the average speed of the particles of the gas)
C. What happens to the speed of the particles when a gas is heated?

D. What happens to volume when a gas is cooled in a container that can change size?

E. What happens to the distance between the particles of a gas when it is cooled?

(Temperature is the average speed of the particles of the gas)
F. What happens to the speed of the particles when a gas is cooled?

Plzzz help it's due today ik I'm dumb but please help me

a. As a container of confined gas is heated, its molecules increase in kinetic energy and push the movable piston outward, resulting in an increase in volume.

B. When you heat them,you essentially give them kinetic energy which increases their speed and hence the distance between molecules increases implying that interatomic forces decreases,leading to change in state from solid to liquid

C. When the gas is heated the particles gain kinetic energy which makes them move faster. This means they collide with the walls more frequently and with greater force and so the pressure increases.

D. Both the increase in pressure and the decrease in temperature cause the volume of the gas sample to decrease. Since both changes are relatively small, the volume does not decrease dramatically.

E. When an object is heated the motion of the particles increases as the particles become more energetic. If it is cooled the motion of the particles decreases as they lose energy.

F. Cooling slows the velocities of the He atoms, causing them to behave as though they were heavier. 6. Both the temperature and the volume are doubled for this gas (n constant), so P remains constant. (a) The number of collisions per unit area of the container wall is constant.

Explanation:

Hope you understand :)

Step-by-step explanation:

We can plug this into a formula and get

the .9075 comes from 1 - the depreciation value of 9.25% which converts to .0925 in decimal form.

? is what we are trying to solve for.

We can divide both sides by 19,700 and we get

so ? is about 13.