Apurple-flowered pea plant is crossed with a white-flowered pea plant. all the f1 plants produced purple flowers. when the f1 plants are allowed to self-pollinate, 401 of the f2s have purple flowers and 131 have white flowers. what are the genotypes of the parental and f1 generation plants?

Parentals: PP (purple) and pp (white)

F1: Pp (purple)

Explanation:

When the two parental plants of differing phenotypes (purple or white flowers) cross, the F1 is 100% purple. This result suggests that the parentals were true breeding (homozygous), with purple flowers being the dominant allele.

When the F1 self pollinates, the F2 shows proportions very similar to 3/4 purple and 1/4 white (401/532 ≅ 3/4 and 131/532 ≅ 1/4). The 3:1 phenotypic ratio is typical of the offspring resulting from a cross between two heterozygous individuals.

The results make sense if the genotypes of the different generations are:

Parentals: PP (purple) X pp (white)

F1:                          Pp (purple)

F2:  1/4 PP, 2/4 Pp, 1/4 pp

Species C.

Explanation:

In a cladogram, any two species which originate from the same branch of the tree, share common ancestry. As we can see in the diagram, the species 1 and 4 have a common touch base with the branch of tree arising out of species C, therefore both species 1 and 4 have some characteristics common /similar to that of the species C.

Therefore answer is species C

PLZ MARK AS BRAINLIST

THIS IS THE RIGHT ANSWER

HOPE IT HELPED

:)