Carbohydrates, more commonly known as sugars, are made up of carbon, oxygen, and hydrogen atoms. the smallest unit of a carbohydrate is a monosaccharide. two monosaccharides make up a disaccharide, and many monosaccharides make up a polysaccharide. disaccharides and polysaccharides can be hydrolyzed back into the individual monosaccharide units. part a select the statement that is incorrect. view available hint(s) select the statement that is incorrect. complex sugars are carbohydrates. all carbohydrates have the general formula cn(h2o)n. simple sugars are carbohydrates. carbohydrates contain only carbon, oxygen, and hydrogen atoms.

All carbohydrates have the general formula Cn(H2O)n

Explanation:

The basic unit of carbohydrates-monosaccharides have the  formula C nH 2nO n while the basic general formula of carbohydrates is Cm(H2O)n .

Monosaccharides are basic units (components) of carbohydrates. Those are simple sugars such as glucose, fructose, galactose. Two monosaccharides can join together via glycosylic  bond and make disaccharides. Some of the disaccharides are: sucrose (glucose + fructose), lactose (galactose + glucose), maltose (glucose + glucose).

Disaccharides can be broken down to monosaccharides by an enzyme called a disaccharidase.

Longer chains of monosaccharides form oligosaccharides (usually as glycolipids ) and polysaccharides (starch, glycogen,cellulose, chitin).

Carbohyrates are important biomolecules included in metabolism, energy storage, they are also structural components, have role in immune response, as coenzymes etc.

#Divide given mass with their molar masses.

C=48.38÷12.01= 4.03mols

H= 6.74÷1.0079= 6.69mols

O= 53.5÷16.00= 3.34mols

#Divide the moles with the lowest mole.

C = 4.03÷3.34 = 1.21

H = 6.69÷3.34 = 2.00

O = 3.34÷3.34 = 1

∴Emperical Formula = CH₂O

#Molar mass of CH₂O = 12.01 + (1.0079 x 2) + 16.00 = 30.02 g/mol

#Divide both moler masses: 180.15g/mol÷30.02g/mol = 6

#Multiply the answer with the Emperical formula to get the Molecular formula: 6 x (CH₂O) = C₆H₁₂O₆

Empirical Formula: CH₂OMolecular Formula: C₆H₁₂O₆

Explanation:

Firstly, you have to divide the three masses of the elements with their respective molar mass to find their moles.  After you've found the moles use the lowest mole to divide the moles of each element again to find your empirical formula. Then you calculate the molar mass of the empirical formula and divide the molar mass with the given molar mass of  finally, multiply the answer with the empirical formula.