During what part of the action potential do voltage-gated na+ channels begin to inactivate (their inactivation gates close)? view available hint(s) during what part of the action potential do voltage-gated na+ channels begin to inactivate (their inactivation gates close)? at the beginning of an action potential, as the membrane potential reaches threshold at the end of the depolarization phase, as the membrane potential approaches its peak value at the end of the hyperpolarization phase of an action potential, as the membrane potential returns to its resting value at the end of the repolarization phase, as the membrane potential briefly passes its resting value

During what part of the action potential do voltage-gated Na+ channels begin to inactivate (their inactivation gates close)? View Available Hint(s) During what part of the action potential do voltage-gated Na+ channels begin to inactivate (their inactivation gates close)? at the beginning of an action potential, as the membrane potential reaches threshold at the end of the depolarization phase, as the membrane potential approaches its peak value at the end of the hyperpolarization phase of an action potential, as the membrane potential returns to its resting value at the end of the repolarization phase, as the membrane potential briefly passes its resting value

Yes, her board is long enough to cut and construct a wooden chair.

Explanation:

Given that the board is 12 inches.

And 1 inch = 2. 54 cms

Now, converting the inches into cm,

we have,

1 inch = 2.54 cms

12 inch= 2.54 × 12

          = 30.48 cms

Now, Susan's board is 30.48 cms while the required length for the wooden chair is 29 cms.

30.48 - 29.00 = 1.48

So, since Susan's board is longer than the required length, she will be able to construct the wooden chair. She will still be left with 1.48 cms of the wooden board.