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sanchezp0821
13.05.2021 •
Biology
Una carga de 50 N unida a un resorte que cuelga verticalmente estira el resorte 5cm. El resorte se coloca ahora horizontalmente sobre una masa y se estira 11cm.
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Ответ:
-110 N
Explanation:
Una carga de 50 N unida a un resorte que cuelga verticalmente estira el resorte 5cm. El resorte se coloca ahora horizontalmente sobre una masa y se estira 11cm. ¿Qué fuerza se requiere para estirar ese resorte en esa cantidad?
Solution:
La constante de resorte (k) es la relación entre la fuerza (F) y la extensión (d) como resultado de la fuerza aplicada, por lo tanto:
k = F / d
Dado que F = 50 N, d = 5 cm = 0.05 m. Por eso:
k = F / d = 50 N / 0.05 = 1000 N / m
La fuerza (F) requerida para provocar un estiramiento de 11 cm se da como:
F = -kx
x = 11 cm = 0,11 m. Por eso:
F = -kx = -1000 * 0,11 = -110 N
El signo negativo significa que el objeto se tira hacia el resorte.
Ответ:
carbon,hydrogen,and oxygen
explanation;