What are the differences in mrnas of cancer cells and normal cells?
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Ответ:
Ответ:
1.54 L
Explanation:
Camels use water obtained from the process of cellular respiration when they use fats as a substrate.
Suppose the fat used during respiration is Tripalmitoylglycerol which contains 3 palmitic acid or Palmitoyl-CoA attached to the esters.
The molecular weight of Tripalmitate is 807 g/mol therefore 1000 g of fat will have 1000/807 = 1.24 moles of Tripalmitate x 3 = 3.72 moles of Palmitoyl CoA.
Now according to the Beta oxidation reaction,
Palmitoyl CoA + 23 O₂+ 108 ADP + 108 Pi > 16 CO₂ + 108 ATP + 23 H₂O + 8 Acetyl CoA
1.23 moles of Palmitoyl CoA produce 23 H₂O therefore
3.72 will produce Palmitoyl CoA will produce= 3.72 x 23 H₂O
= 85.56 H₂O molecules.
Now, 85.56 H₂O molecules will yield
= 85.56 x 18 ( MW of water=18)
= 1541.8 g
= 1.54 L
Thus, 1.54 L is correct.