0.12M NaOH solution to neutralize Oxalic acid solution. you will need the molecular weight of the Oxalic acid
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Ответ:
2 NaOH (aq) + H2C2O4(aq) Na2C2O4(aq) + 2H2O (l) Moles of NaOH used = Molarity x Volume (L) = 0.12 mole/L x 0.025
Explanation:
Ответ:
HCl
Explanation:
Hydrochloric acid is oxidized to water