1.Calcula la intensidad que circula por la resistencia de un circuito de 100 Ω cuando está sometida a una tensión de 4 V.

Respuesta:

I = 0.04 A

Explicación:

Paso 1: Información provista

Paso 2: Calcular la intensidad de la corriente que circula por la resistencia de un circuito

Podemos calcular la intensidad de corriente usando la Ley de Ohm.

I = V/R

I = 4 V / 100 Ω

I = 0.04 A

La unidad de intensidad de corriente es Ampere.

Van´t Hoff factor assuming 0 % ionization is 1, while when ionization is 100 % the factor is 3.

Explanation:

The study of colligative properties is different for ionic substances than for non-ionic substances. This is related with the fact that when  ionic compounds are dissolved, they separates in their constitutive ions. In contrast, when a non-ionic compound is dissolved, there are only one type o molecule in the solution. This fact affect the estimation of colligative properties and for this reason Van´t Hoff factor was introduced.

Van´t Hoff factor = number of particles after disociation/ number of particles before disociation.

The disociation of H2SO4 is represented as:

H2SO4 ⇔ 2 H+  + SO4-

- Assuming 0 % inization:

Van´t Hoff factor = 1/ 1 ⇒Van´t Hoff factor = 1.

-Assuming 100 % Ionization

Van´t Hoff factor = 3/ 1 ⇒Van´t Hoff factor = 3.

Summarizing, Van´t Hoff factor assuming 0 % ionization is 1, while when ionization is 100 % the factor is 3.