1.dH = Vdp + Tds is valid only if? 2.A closed system that does not change mechanical work and heat with the environment evolves spontaneously in the sense

3. An isolated system evolves spontaneously in the sense…

A. decrease in Helmholtz free energy;

B. increase in entropy;

C. decrease in enthalpy;

D. decrease in Gibbs free energy;

E. none of the answers correspond.

The answers to the questions are as follows

The temperature of the water bath goes upThe piston moves outHeat flows out of the gaseous mixture173.kJ flows out of the system

Explanation:

From the question, it is noted that 173.kJ of heat flows out of the system into the insulated water bath therefore the temperature of the water bath goes up

as seen in the relation ΔH = m·c·ΔT

Where ΔH heat measured by temperature  rise ΔT of a given mass of water m of specific heat capacity of 4.2 J/g°C

The amount of heat measured from previous experiment is more than the heat from the present reaction therefore since in the present reaction is constant pressure and from the first law of thermodynamics Energy can neither be created nor destroyed, the balance heat will be transformed to work evidence in the piston moving out

ΣH = Q + W  where

w = P × ΔV = P × (P₂ - P₂)

Heat flows out of the gaseous mixture and is sensed from the rise in the temperature of the water bath173.kJ flows out of the system