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20.04.2020 •
Chemistry
1) How many sulfur atoms are there in 21.0 g of Al2S3? A) 8.42 1022 atoms D) 6.02 1023 atoms B) 2.53 1023 atoms E) 6.30 1026 atoms C) 2.14 1023 atoms Ans) B
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Ответ:
In 21 grams of Al2S3 we have 2.53 *10^23 S atoms (optionB is correct)
Explanation:
Step 1: Data given
Mass of Al2S3 = 21.0 grams
Molar mass of Al2S3 = 150.158 g/mol
Number of Avogadro = 6.022 * 10^23 / moles
Step 2: Calculate moles of Al2S3
Moles Al2S3 = mass Al2S3 / molar mass Al2S3
Moles Al2S3 = 21.0 grams / 150.158 g/mol
Moles Al2S3 = 0.140 moles
Step 3: Calculate moles sulfur
For 1 mol Al2S3 we have 3 moles S
For 0.140 moles Al2S3 we have 3*0.140 = 0.420 moles S
Step 4: Calculate sulfur atoms
Number of sulfur atoms = moles * Number of Avogadro
Number of sulfur atoms = 0.420 moles * 6.022 * 10^23 / moles
Number of sulfur atoms = 2.53 *10^23 S atoms
In 21 grams of Al2S3 we have 2.53 *10^23 S atoms (optionB is correct)
Ответ:
This requires listening, the rest do not