1) Of the following transitions in the Bohr hydrogen atom, the transition results in the emission of the highest-energy photon. A) n = 1 → n = 6 B) n = 6 → n = 1 C) n = 6 → n = 3 D) n = 3 → n = 6 E) n = 1 → n = 4

B. n = 6 → n = 1

Explanation:

B: n=6, n=1 is highest-energy photon. Emission is going from a higher energy level down to a lower energy level, so that will rule out a,d,e. So between b and c, it will be b because if you study the n=1 energy level you will see that it is the ground state energy level, which means that energy is the greatest in this energy level.

Yet both compounds and elements are considered pure substances. Pure compounds are created when elements combine permanently, forming one substance. For example, when the elements mercury and oxygen combine, and a chemical reaction takes place, mercury (II) oxide is created.

Hope this helps!