1. when two atoms with different electronegativities are bonded together, a bond dipole exists. these are displayed with an arrow originating at the atom with the electronegativity and pointing toward the atom with the electronegativity.
2. partial charges will exist on each atom when a bond exists between two atoms with different electronegativities. since the atom with a higher electronegativity will have a stronger ability to attract electrons, it will have a partial charge. the atom with a lower electronegativity will have an equal and opposite charge. as the difference in electronegativity increases, the resulting magnitudes of the partial charges will

In order: LOWER, HIGHER, NEGATIVE, POSITIVE, INCREASE

Explanation:

First you must consider the definition of electronegativity.

All in all, electronegativity is the ability of an atom to attract electrons to itself. For this explanation, let's just consider the groups 1, 2, 13-17, and the noble gases of the periodic table. Furthermore, let's also consider the octet rule. The octet rule says that the last orbit of an atom tends to have 8 electrons in order to be stable.

If you take an atom like Sodium (Na) and search its distribution of electrons by levels, you'll see these number in the last two orbits: 8.1

The penultimate orbit has 8 electrons and the last one has only 1. Therefore, in order to futfill the octet rule what do you think it's easier? Losing the last electron and leaving the 8 electrones of the penultimate orbit as last orbit? Or maybe taking 7 electrons for the last orbit and, hence, futfilling the octet? Well, the answer is the first case.

The more you move from group to group (i.e, rightwards in the periodic table), more electrons will have in their last orbit.

So, in order to respond your question: Yes you should display it like this:

A --> B

Consider A and B two random atoms, for which B's electronegativity is higher than A's. This arrow shows the tendency of the electron flow.

As electrons go to the more electronegative atom, the whole electronic ''cloud'' will tend to be closer to B, because this atom is more electronegative. Hence, there will be a partial (not fixed) negative charge on B rather than on A. This is due to B's high electronegativity. This means that the negative charge will spend more time on B rather than on A, this is what partial negative charge means.

The higher the electronegativity is, the higher the magnitudes of the partial charges --> Therefore, these partial charges are increased and sometimes it might lead to the chemical bond breakage.

C=1

A=2

F=3

E=4

Hope this helps good luck