15.A mixture of methane and oxygen gases, in a 8.77 L flask at 80 °C, contains 3.25 grams of methane and 4.08 grams of oxygen. The partial pressure of oxygen in the flask is atm and the total pressure in the flask is
atm.
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Partial pressure of oxygen =  0.43 atm

Total pressure = 1.0 atm

Explanation:

Given data:

Volume of flask = 8.77 L

Temperature = 80°C (80 + 273.15 K = 353.15 K)

Mass of methane = 3.25 g

Mass of oxygen = 4.08 g

Partial pressure of oxygen = ?

Total pressure = ?

Solution:

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 3.25 g/ 16 g/mol

Number of moles = 0.2 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.08 g/ 32 g/mol

Number of moles = 0.13 mol

Total number of moles in flask = 0.13 mol + 0.2 mol = 0.33 mol

Pressure of oxygen:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

P ×8.77 L = 0.13 mol × 0.0821 atm.L/mol.K  × 353.15 K

P = 3.77atm.L /8.77 L

P =  0.43 atm

Pressure of flask:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

P ×8.77 L = 0.33 mol × 0.0821 atm.L/mol.K  × 353.15 K

P = 8.75atm.L /8.77 L

P =  1.0 atm

(Answer) The name of the compound with formula N2Cl4 is dinitrogen tetrachloride.

In this compound, two central nitrogen atoms are bonded by covalent bonds by sharing valence electron pairs among each other. Two chlorine atoms are attached to each nitrogen atom by covalent bond formation.

One molecule of the compound N2Cl4 has 2 nitrogen atoms and 4 chlorine atoms. For this reason, its name is dinitrogen tetrachloride. Here, "di" represents "two" and "tetra" represents "four".