2. consider the following reaction: 4 fes2 + 11o2 → 2 fe2o3 + 8 so2
when 26.62 moles of fes2 reacts with 59.44 moles of o2, what are the limiting and
excess reactants?

Oxygen gas (O₂) is the rate limiting reactant and FeS₂ is the excess reactant.

Explanation:

From the questions we are given;

4FeS₂(s) + 11O₂(g) → 2Fe₂O₃(s) + 8SO₂(s)

Moles of FeS₂ are 26.62 moles Moles of Oxygen, O₂ are 59.44 moles

We are supposed to determine the limiting and excess reactants;

From the equation of the reaction given; 4 moles of FeS₂ required 11 moles of Oxygen gas.

Working with the amount of reactants given;

26.62 moles of FeS₂ will require 73.205 moles of O₂ and only 59.44 moles of O₂ are available.On the other hand 59.44 moles of O₂ requires 21.615 moles of  FeS₂, and we are given 26.62 moles of FeS₂ which means FeS₂ is in excess.

Conclusion;

We can conclude that Oxygen gas (O₂) is the rate limiting reactant and FeS₂ is the excess reactant.

why is it asked in the chemistry isnt it maths question though