Chemistry: 2055 Q. No. 10^-2 mole of KOH is dissolved in 10 litres ofwater. What will be the pH of the solution?12Ans: pH = 11

2055 Q. No. 10^-2 mole of KOH is dissolved in - id20551021010156407, slimt3763

ginareyes0423

16.03.2022

Explanation:

Moles of KOH = $10^{-2}$

Volume of water = 10 liters

Concentration of KOH is given by

$[KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}$

[KOH] is strong base so we have the following relation

$[KOH]=[OH^{-}]=10^{-3}\ \text{M}$

$pOH=-\log [OH^{-}]=-\log10^{-3}$

$\Rightarrow pH=14-3=11$

So, pH of the solution is 11

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paytonhuff8580

17.11.2022

x=2

Step-by-step explanation

5x-10=0

fist add 10 to both sides to cancel the -10 on the left side

5x=10

then divide both sides to cancel the 5 in front of the x and to get the x all by itself

x=2

and then you have your answer!

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