gunnatvinson
05.11.2020 •
Chemistry
2Al(s) + 3CuSO4(aq) --> Al2(SO4)3(aq) + 3Cu(s) 2. According to the reaction in question 1 above, how many grams of solid copper will theoretically be produced when 2.2 g of aluminum are reacted with 14.4 g of copper(II) sulfate? Which reactant is the limiting reactant? Show your work for this problem
Solved
Show answers
More tips
- A Art and Culture The History and Characteristics of Jazz Bands: A Deep Dive...
- W Work and Career Can Skill Alone Make You a Professional?...
- F Family and Home Daughter says: If you don t want to do it, don t do it. Should we persuade her?...
- S Science and Technology How to Secure Exam Sessions: Silence Mobile Phones in the Classroom...
- C Computers and Internet Which Phone is Best for Internet Surfing?...
- P Philosophy Is Everything We Strive for Eventually Achieved and Destroyed?...
- S Society and Politics Understanding Politics and Its Role in the Development of Civilization...
- P Philosophy Why Did God Create Man and Place Him in Obscurity?...
- S Society and Politics Skoptsy: Who They Are and How They Perform Castration?...
- O Other Childhood Fears: What Many of Us Experienced...
Answers on questions: Chemistry
- C Chemistry Why can t you balance a chemical equation by changing the subscript?...
- E English Which sentence correctly uses the DASHES...
- H History What was the stamp act? how did it contribute to the start of the american revolution?...
- M Mathematics What is the equation of the line that gors through (1,-2) and has an undefined slope...
- B Business Complete the sentences with the correct term. Some options can be used more than once, and some may not be used at all! help thanks!...
Ответ:
5.73 g of solid copper, can be theoretically produced in this reaction.
Explanation:
We start from the begining with the balanced equation:
2Al (s) + 3CuSO₄ (aq) → Al₂(SO₄)₃ (aq) + 3Cu (s)
To determine the limiting reactant we need to know the moles of each.
2.2 g / 26.98 g/mol = 0.0815 moles of Al
14.4 g / 159.6 g/mol = 0.0902 moles of copper (II) sulfate.
Ratio is 2:3. Let's find out the limtiing reactant,
2 moles of Al react to 3 moles of copper (II) sulfate
Then 0.0815 moles of Al, may react to (0.0815 . 3) / 2 = 0.122 moles of salt.
We only have 0.0902 moles of sulfate and we need 0.122 moles to complete the reaction, as the sulfate we have, is not enough, the salt is the limting reagent. We use this to determine the solid copper that can be theoretically produced.
This ratio is 3:3, so If we have 0.0902 moles of copper (II) sulfate, we may produce 0.0902 moles of solid copper.
Let's conver the moles to mass → 0.0902 mol . 63.5 g/mol = 5.73 g
Ответ:
Human ears can hear sound waves that vibrate in the range from about 20 times a second (a deep rumbling noise) to about 20,000 times a second (a high-pitched whistling). (Children can generally hear higher-pitched sounds than their parents, because our ability to hear high frequencies gets worse as we get older.) Speaking more scientifically, we could say that the sounds we can perceive have a frequency ranging from 20–20,000 hertz (Hz). A hertz is a measurement of how often something vibrates and 1 Hz is equal to one vibration each second. The human voice makes sounds ranging from a few hundred hertz to a few thousand hertz.
Suppose you could somehow hit a drum-skin so often that it vibrated more than 20,000 times per second. You might be able to see the skin vibrating (just), but you certainly couldn't hear it. No matter how hard you hit the drum, you wouldn't hear a sound. The drum would still be transmitting sound waves, but your ears wouldn't be able to recognize them. Bats, dogs, dolphins, and moths might well hear them, however. Sounds this like, with frequencies beyond the range of human hearing, are examples of ultrasound.
Ultrasound is sound or other vibrations having an ultrasonic frequency, particularly as used in medical imaging. Also, Infrasound is sound waves with frequencies below the lower limit of human audibility