2na(s) + 2h2o(l) → 2naoh(aq) + h2(g) when 2 moles of na react with water at 25°c and 1 atm, the volume of h2 formed is 24.5 l. calculate the magnitude of work done in joules when 0.45 g of na reacts with water under the same conditions. (the conversion factor is 1 l · atm = 101.3 j.)
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Ответ:
Magnitude of work done = 24.28 J
Explanation:
No. of moles = Reacting mass/ Molar mass
Reacting mass of Na = 0.45 g
Molar mass of sodium = 23g/mol
∴ No. of moles of sodium = 0.45/23 = 0.0196 mole
If 2 moles of Na react with water at 25°C and 1 atm, 24.5 L of H₂ was formed.
∴ when 0.0196 mole of Na react with water under the same conditions, (24.5×0.0196)/2 L of H₂ will be formed.
⇒ (24.5×0.0196)/2 L = 0.24 L
0.24 L × 1 atm = 0.24 L . atm
Since 1 L · atm = 101.3 J
∴ 0.24 L . atm = (0.24 L . atm ×101.3)/1 = 24.28 J
Magnitude of work done = 24.28 J
Ответ:
See below
Step-by-step explanation:
Given points:
S(-3,6),T(0,7),U(1,4),and V(-5,2)Translation rule:
(x,y) → (x+7,y-9)New coordinates by applying the rule:
S'(4, -3), T'(7, -2), U'(8, -5), V'(2, -7)See attached for the graph
The blue trapezoid is STUV and the red one is S'T'U'V'