3.0 l of a gas is at a temperature of 78 degrees celsius. find the volume of the gas at standard temperature

= 2.33 L

Explanation:

Using the Charles law.

V1/T1 = V2/T2

V1 = 3.0 L

T1 = 78 + 273

    = 351 K

At s.t.p the temperature is 273 K and pressure is 1 atm.

V2 = ?

T2 = 273 K

V2 = V1T2/T1

     = (3.0 ×273)/351

     = 2.33 L

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