307 g of an unknown mineral is heated to 98.7 °c and placed into a calorimeter that contains 72.4 g of water at 23.6 °c. the heat capacity of the empty calorimeter was 15.7 j/k. the final temperature of the calorimeter was 32.4 °c. what is the specific heat capacity of the mineral in j/gk?

0.138 J/g.K

Explanation:

According to the law of conservation of energy, the sum of the heat released bt he mineral and the heats absorbed by the water and the calorimeter is equal to zero.

Qm + Qw + Qc = 0

Qm = - Qw - Qc   [1]

The heat absorbed by the calorimeter can be calculated using the following expression.

Q = C . ΔT

where,

C is the heat capacity

ΔT is the change in temperature

The heat released by the mineral and the one absorbed by the water can be calculated using the following expression.

Q = c . m . ΔT

where,

c is the specific heat capacity

m is the mass

ΔT is the change in temperature

Replacing in [1],

1. Plasma is "the state..." because plasma is rarely natural on earth (only lightning strikes) and has the highest temp

gas is "particles move freely" they do move freely

liquid is "it expands to fill volume" they do not have definite boundaries so they fill up the container

solid is "it retains its shape" yup dis is pretty obvious ig

2.

I agree with your answers.

it wouldnt be hypothesis or theory because they are basically the same thing and they explain facts. fact would be the best answer

conduct experiments would be the most logical here because you can gain new knowledge from conducting experiments instead of the rest.