greyxxamber
06.04.2021 •
Chemistry
3Cl2 + 2N2 - 2N, C13
Moler masses:
chlorine gas = 70.9 g/mol
nitrogen gas = 28.02 g/mol
dinitrogen trichloride = 134.27 g/mol
A. 1.98 mol of chlorine reacts with 1.98 moles of nitrogen. What is the limiting reactant? (chlorine)
B. What mass of dinitrogen trichloride is produced from the reaction? (177.2364)
C. How many moles of the excess reactant is left over? (0.66)
D. If the percent yield of dinitrogen trichloride is 95.5%. what is the actual yield of the product? (169.2607)
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Ответ:
Moles = \frac{1.98}{70.9}=0.0279Moles=
70.9
1.98
=0.0279
Ответ:
explanation:
so what's the question? ?