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eelebron0905
13.01.2021 •
Chemistry
4. How many grams of acetylene would be given off if the limiting reagent in the reaction is calcium carbide and you start with 2.00 g
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Ответ:
0.78 g of acetylene.
Explanation:
The equation of the reaction is;
CaC2(s) + 2H2O (l) > Ca(OH)2(aq) + C2H2(g)
We have been told that CaC2 is the limiting reactant.
Number of moles of CaC2 = 2g/ 64 g/mol = 0.03 mol
If 1 mole of CaC2 yields 1 mole of acetylene
0.03 moles of CaC2 yields 0.03 moles of acetylene
Mass of acetylene = number of moles * molar mass
Molar mass of acetylene = 26 g/mol
Mass of acetylene = 0.03 moles * 26 g/mol
Mass of acetylene = 0.78 g of acetylene.
Ответ:
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