[50 Points] In the experiment below, Beaker 1 contains 12.0 M HCl. Each subsequent beaker is diluted by 50%. What is the [OH-] in Beaker 6?
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Ответ:
2.67x10⁻¹⁴M = [OH-]
Explanation:
To solve this question we need first to find the HCl concentration of the beaker 6. Then, using:
Kw = [OH-][H+]
Where Kw = 1x10⁻¹⁴
[OH-] is our incognite
[H+] is = [HCl]
Beaker 2 = 12.0M / 2 = 6.0M
Beaker 3 = 6.0M / 2 = 3.0M
Beaker 4 = 3.0M / 2 = 1.5M
Beaker 5 = 1.5M / 2 = 0.75M
Beaker 6 = 0.75M / 2 = 0.375M
HCl = 0.375M = [H+]
1x10⁻¹⁴ / [H+] = [OH-]
1x10⁻¹⁴ / 0.375M = 2.67x10⁻¹⁴M
2.67x10⁻¹⁴M = [OH-]Ответ:
Object labels are the smallest of the museum labels. Their scope is limited to the individual objects they are displayed next to. Typically, the title of the work or a descriptive title phrase is given, followed by the name and often, the dates of the artist, and the date and place the object was created.
Explanation:
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