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shealwaysknows23
16.03.2020 •
Chemistry
A 0.4-m3 rigid tank contains 0.6 kg of N2 and 0.4 kg of O2 at 300 K. Determine the partial pressure of each gas and the total pressure of the mixture. The gas constant for N2 is 0.2968 kPa·m3/kg·K and the gas constant for O2 is 0.2598 kPa·m3/kg·K.
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Ответ:
Total pressure → 2.08 atm
Partial pressure N₂ → 1.31 atm
Partial pressure O₂ → 0.76 atm
Explanation:
To determine the total pressure of the mixture we need to know the total moles of the gases:
Sum of moles from gases at the mixture = Total moles (Dalton's law)
We convert the mass from kg to g and then, we states the moles of each:
0.6 kg . 1000g/ 1kg = 600 g // 0.4g . 1000g/ 1kg = 400 g
600 g . 1 mol/28g = 21.4 moles of N₂
400 g . 1mol/32g = 12.5 moles of O₂
Total moles → 21.4 + 12.5 = 33.9 moles
Before to replace the data in the Ideal Gases Law, we notice that the volume is in m³. (1000 dm³ = 1 m³ and 1dm³ = 1L)
0.4m³ . 1000 dm3 / 1m³ = 400 dm³ → 400L
Now, we can put the data on the Ideal Gases Law:
400L . P = 33.9 mol . 0.082L.atm/mol.K . 300K
P = (33.9 mol . 0.082L.atm/mol.K . 300K) / 400L → 2.08 atm
We apply the mole fraction for the partial pressures of each gas:
Moles of N₂ / Total moles = Partial pressure N₂ / Total pressure
Moles of O₂ / Total moles = Partial pressure O₂ / Total pressure
Partial pressure = Total pressure . (Moles of the gas / Total moles)
Partial pressure N₂ = 2.08 atm . (21.4 mol / 33.9 moles) → 1.31 atm
Partial pressure O₂ = 2.08 atm . (12.5 mol / 33.9 moles) → 0.76 atm
Ответ:
pN2 = 133.56 kPa
pO2 = 77.94 kPa
Total pressure = 211.5 kPa
Explanation:
Step 1: Data given
Volume of the tank = 0.4 m³
Mass of N2 = 0.6 kg
Mass of O2 = 0.4 kg
Temperature = 300 K
The gas constant for N2 is 0.2968 kPa*m3/kg*K
The gas constant for O2 is 0.2598 kPa*m3/kg*K
Step 2: Calculate the partial pressures
pN2 = MRT / V = (0.6 * 0.2968 * 300)/0.4
pN2 = 133.56 kPa
pO2 = (0.4 * 0.2598 * 300)/ 0.4
pO2 = 77.94 kPa
Step 3: Calculate total pressure
Total pressure = 133.56 kPa + 77.94 kPa
Total pressure = 211.5 kPa
Ответ:
Nitrogen gained 4 electrons.
Because Nitrogen's redox number went from +6 to +2, it must have gained 4 electrons (-4) in order to achieve this number. Thus, Nitrogen is reduced.