A 0.91 L of a solution of 2.0 M HCI can be prepared with what?

Explanation:

HCl can be obtained with different concentrations of HCL in water.

If for example, you purchased 37.2% HCL it would have a density of 1.2 g/mL. The molecular weight of HCl is 36.46 g/mole

1.2g/mL x 1000 ml/L = 1200 g/L = 1200g/L x 0.372 =(446.4g HCl/L)/36.46 g/mole = 12.2 M/L HCl

To prepare a 2M solution:

V1 = ?, M1 = 12.2M

V2 = 1L, M2 = 2M

V1*M1=V2*M2

V1 = (V2*M2)/M1

V1 = 1*2/12.2 = 0.164 L or 164 mL of 12.2M HCl diluted to 1 Liter with water will yield a 2M solution.

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