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17.03.2020 •
Chemistry
A 1.00 L flask is filled with 1.15 g of argon at 25 ∘C. A sample of ethane vapor is added to the same flask until the total pressure is 1.350 atm . Part A What is the partial pressure of argon, PAr, in the flask?
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Ответ:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001![m^{3}](/tpl/images/0549/7791/2b022.png)
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13![\frac{J}{kg k}](/tpl/images/0549/7791/b6c11.png)
From ideal gas equation P V = m RT
⇒ P =![\frac{m R T}{V}](/tpl/images/0549/7791/897f0.png)
Put all the values in above formula we get
⇒ P =
× 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
Ответ:
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print("Consonants =",consonants)
Explanation: