A 20.00 mL Ba ( OH ) 2 solution of unknown concentration was neutralized by the addition of 42.50 mL of a 0.1255 M HCl solution. Write the balanced molecular equation for the neutralization reaction between HCl and Ba ( OH ) 2 in aqueous solution. Include physical states. molecular equation: Ba^{2+}(aq) +2OH^{-}(aq) +H^{+}(aq) +Cl^{-}(aq)<=>H_{2}O(l) +Ba^{2+}(aq) +Cl^{-}(aq) Ba 2 + ( aq ) + 2 OH − ( aq ) + H + ( aq ) + Cl − ( aq ) − ⇀ ↽ − H 2 O ( l ) + Ba 2 + ( aq ) + Cl − ( aq ) Calculate the concentration of Ba ( OH ) 2 in the original 20.00 mL solution. [ Ba ( OH ) 2 ] = M Calculate the concentrations of Ba 2 + and Cl − in solution following the neutralization reaction.
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Ответ:
The concentration of
ions in the solution are 0.0426 M and 0.0852 M respectively
Explanation:
Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.
The chemical equation for the reaction of HCl and barium hydroxide follows:
![2HCl(aq.)+Ba(OH)_2(aq.)\rightarrow BaCl_2(s)+2H_2O(l)](/tpl/images/0526/5513/8e1f5.png)
To calculate the concentration of acid, we use the equation given by neutralization reaction:where,
We are given:
Putting values in above equation, we get:
![1\times M_1\times 20.00=1\times 0.1255\times 42.50\\\\M_1=\frac{1\times 0.1255\times 42.50}{1\times 20.00}=0.267M](/tpl/images/0526/5513/54e2a.png)
To calculate the number of moles for given molarity, we use the equation:Molarity of HCl solution = 0.1255 M
Volume of solution = 42.50 mL = 0.04250 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
By Stoichiometry of the reaction:
2 moles of HCl produces 1 mole of barium chloride
So,
of HCl will produce = ![\frac{1}{2}\times 5.33\times 10^{-3}mol=2.665\times 10^{-3}mol](/tpl/images/0526/5513/8fc2d.png)
Calculating the concentration of barium chloride by using equation 1:Moles of barium chloride =![2.665\times 10^{-3}mol](/tpl/images/0526/5513/1fd17.png)
Volume of solution = [20.00 + 42.50] mL = 62.5 mL = 0.0625 L
Putting values in equation 1, we get:
1 mole of barium chloride produces 1 mole of barium ions and 2 moles of chloride ions
So, concentration of barium ions = 0.0426 M
Concentration of chloride ions = (2 × 0.0426) = 0.0852 M
Hence, the concentration of
ions in the solution are 0.0426 M and 0.0852 M respectively
Ответ:
t6666666666644444444444444444444444
Explanation: