A 87.0 mL87.0 mL aliquot of a 0.400 M0.400 M stock solution must be diluted to 0.100 M.0.100 M. Assuming the volumes are additive, how much water should be added
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Ответ:
Explanation:
Liquid given = 87 mL of .4 M
concentration required = .1 M .
we shall apply the formula
S₁ V₁ = S₂ V₂
S represents concentration and V represents volume
.4 x 87 = .1 V₂
V₂ = 348 mL .
So water to be added = 348 - 87 = 261 mL.
Ответ: