A ball of mass 0.3 kg is released from rest at a height of 8 m. How fast is it going when it hits the ground? Acceleration due to gravity is g = 9.8 m/s2.
Group of answer choices
2.4 m/s
8.2 m/s
12.5 m/s
13.1 m/s
Solved
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Ответ:
C. 12.5 m/s
Explanation:
h = h(0) - gt²/2
0 m = 8 m - 9.8 m/s²*t²/2
- 8 m = - 9.8 m/s²*t²/2
16 m = 9.8 m/s² * t²
t² = 16/9.8 s²
t = √(16/9.8) s
v = v(0) + gt
v = 0 +gt
v = 9.8 m/s² * √(16/9.8) s ≈ 12.5 m/s
Ответ:
A. Angles 1 and 5 are congruent corresponding angles
Step-by-step explanation: