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JuanTorres7
05.05.2020 •
Chemistry
A balloon inflated at 25oC has a volume of 3.4 L. The balloon expands to 3.7 L. Assuming constant pressure, what is the new temperature?
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Ответ:
T2=324.29k
Explanation:
V1=3.4L T1=25+273=298k
V2=3.7L T2=?
V1 V2
=
T1 T2
T2= V2×T1/V1
T2=(3.7×298)/3.4
T2=324.29k
Ответ: