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banna01man
10.02.2021 •
Chemistry
a box of spherical candies is 23 g and its volume is 32.3 cm^3. If the average mass of a single jawbreaker is 0.94g, what is the radius of a single jawbreaker?
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Ответ:
T₂ = 687.6 K
Explanation:
Given data:
Initial pressure = 108 Kpa = 108/101 = 1.06588 atm
Initial temperature = 20°C = 20+273.15 = 293.15 k
Final temperature = ?
Final pressure = 2.50 atm
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
1.06588 atm / 293.15 K = 2.5 atm/T₂
T₂ = 2.5 atm ×293.15 K / 1.06588 atm
T₂ = 732.875 atm. K /1.06588 atm
T₂ = 687.6 K