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kiaramccurty
18.08.2020 •
Chemistry
A chemist adds 190.0mL of a 1.90M nickel(II) chloride NiCl2 solution to a reaction flask. Calculate the millimoles of nickel(II) chloride the chemist has added to the flask. Round your answer to 3 significant digits.
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Ответ:
361.0 milimoles of nickel chloride
Explanation:
Mili is a unit prefix that represents 1/1000 of the measured value. The multiplication of molarity with volume in liters gives the moles:
190.0mL = 0.190L * (1.90 moles / L) = 0.361 moles -Are moles of NiCl2.
Now, to convert moles to milimoles you must use 1 mole = 1000 milimoles thus:
0.361 moles * (1000 milimoles / 1 mole) =
361.0 milimoles of nickel chlorideОтвет:
A localized bond pair travels between two atoms. A bond pair that moves between two different pairs of atoms is considered delocalized. You can identify delocalized bonds by checking the electron locations in two different resonance forms; if the pair changes location and form, it is delocalized.