A chemist determined by measurements that 0.0650 moles of gallium participated in a chemica reaction. Calculate the mass of gallium that participated in the chemica reaction
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Ответ:
4.53gm
Explanation: n=m/M
n is # of moles
m is mass
M is molar mass
so m=n*M when you rearrange the equation
Ответ:
There are 9 hydrogen atoms in the given chemical formula.
Explanation:
We are given a chemical formula of ammonia which is![NH_3](/tpl/images/0129/4280/b033f.png)
This molecule is formed by the combination of hydrogen and nitrogen atoms.
In 1 mole of ammonia, 1 atom of nitrogen is there and 3 atoms of hydrogen is there.
We are given:
Moles of ammonia = 3
So, 3 atoms of nitrogen is there and 9 atoms of hydrogen is there.
Hence, there are 9 hydrogen atoms in the given chemical formula.