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adityamahesh2002
05.05.2020 •
Chemistry
A chemist prepares hydrogen fluoride by means of the following reaction: CaF2 + H2SO4 —> CaSO4 + 2HF
The chemist uses 11g of CaF2 and an excess of H2SO4, and the reaction produces 2.22g of HF.
A) calculate the theoretical yield of HF
B) Calculate the percent yield of HF
pls hel!!
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Ответ:
a) Theoretical mass of HF from the reaction = 5.64 g
b) Percent yield of HF = 39.36%
Explanation:
CaF2 + H2SO4 —> CaSO4 + 2HF
11g of CaF2 and an excess of H2SO4
This means that CaF2 is the limiting reagent. The limiting reagent determines how much products will be formed.
a) The theoretical yield of HF will be obtained from the stoichiometric balance of the reaction.
We first convert the 11g of CaF2 into number of moles.
Number of moles = (mass)/(molar mass)
Molar mass of CaF2 = 78.07 g/Lol
Number of moles of CaF2 = (11/78.07) = 0.141 moles.
From the balanced reaction,
1 mole of CaF2 gives 2 moles of HF
0.141 mole of CaF2 will give (2×0.141) mole of HF; that is, 0.282 moles of HF
Theoretical Mass of HF from the reaction
= (Number of moles of HF) × (Molar mass)
Molar mass of HF = 20.01 g/Lol
Theoretical mass of HF from the reaction
= 0.282 × 20.01 = 5.64 g
b) Percent yield = 100% × (Actual yield)/(Theoretical yield)
= 100% × (2.22/5.64)
= 39.36%
Hope this Helps!!!
Ответ:
Explanation:
To find the mole ratio, we must use the coefficients.
This equation is balanced (4 atoms of P and 12 atoms of Br on both sides), so we can go straight to the coefficients.
P₄ doesn't have a coefficient, so 1 is implied Br₂ has a coefficient of 6PBr₃ has a coefficient of 4So according to the coefficients above, for every 1 mole of P₄ that is consumed, 4 moles of PBr₃ are produced. Therefore, the ratio is 1 mole P₄ to 4 moles of PBr₃.