Chemistry: A closed cylinder is filled with CO₂ gas. The mass of CO₂ in cylinder is 4.4 g. Now express this amount of Carbon dioxide in following terms: a) no. of moles of CO₂ molecules b) Volume at NTP c) No. of gram molecule d) No. of CO₂ molecules e) No. of carbon atoms f) No. of mole of Oxygen atoms g) No. of molecules of oxygen

A closed cylinder is filled with CO₂ gas. The

swaggaming941

26.09.2021

Molar mass of CO2=44g/mol

given mass=4.4g

$\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:Mass}{Molar\;Mass}=\dfrac{4.4}{44}=0.1mol$

At NTP 1mol weigh 22.4L

0.1mol weigh:-

$\\ \sf\longmapsto 22.4(0.1)=2.24L$

No of molecules=Moles×Avagradro No

$\\ \sf\longmapsto 0.1\times 6.023\times 10^{22}=6.023\times 10^{21}molecules$

CO_2 has 3atoms

No of molecules=

$\\ \sf\longmapsto 3\times 6.023\times 10^{21}=18.069\times 10^{21}molecules$

CO2 has 1carbon

$\\ \sf\longmapsto No\:of\:molecules=6.023\times 10^{21}molecules$

Lets write balanced equation

$\\ \sf\longmapsto C+O_2=CO_2$

1mol of Oxygen exists

It has 2oxygen atoms

$\\ \sf\longmapsto No\:of\:molecules=2(6.023\times 10^{21})=12.046\times 10^{21}$

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