. A container with a volume of 0.50 L contains air at a pressure of 1.0 atm. If the volume is reduced to 0.10 L at constant temperature, what will be the resulting pressure of the air inside? 5.0

The answer to your question is Pressure = 5 atm

Explanation:

Data

Volume 1 = V1 = 0.5 l

Pressure 1 = P1 = 1 atm

Volume 2 = V2 = 0.1 l

Pressure 2 = P2 = x

Formula

To solve this problem use the Boyle's equation

                      V1P1 = V2P2

Solve for P2

                     P2 = V1P1/V2

Substitution

                     P2 = (0.5 x 1) / 0.1

Simplification

                     P2 = 0.5/0.1

Result

                     P2 = 5 atm          

The individual molecules of water while boiling will move fastest amongst the given choices. As the boiling of water will cause the liquid molecules to increase the intermolecular forces of attraction between molecules and get escaped into vapors. Here, there is a transformation of state that is about to occur from liquid to gaseous. Compared to other examples, where there are no change of state occurring.