A covalent compound that shares two pairs of electrons.

Ответ:

Clerry

27.04.2021

a. P_2=8.03atm

b. V_2=0.024L=24mL

Explanation:

Hello,

a. In this case, we use the Boyle's law as en inversely proportional relationship between pressure and volume:

P_1V_1=P_2V_2

Thus, for the given conditions, one computes the new pressure as shown below:

$P_2=\frac{P_1V_1}{V_2} =\frac{18.3mmHg*50.0L}{150.0mL*\frac{1L}{1000mL} }*\frac{1atm}{760mmHg} \\ \\P_2=8.03atm$

b. Now, we should find the final volume for a new pressure of 10 atm:

$V_2=\frac{P_1V_1}{P_2} =\frac{50.0L*18.3mmHg*\frac{1atm}{760mmHg} }{50atm}\\ \\V_2=0.024L=24mL$

Best regards.

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