Jakyramason
05.05.2020 •
Chemistry
A galvanic cell is powered by the following redox reaction: Br2 H2 2OH Answer the following questions about this cell. If you need any electrochemical data, be sure you get it from the ALEKS Data tab. Write a balanced equation for the half-reaction that takes place at the cathode. Write a balanced equation for the half-reaction that takes place at the anode. Calculate the cell voltage under standard conditions. Round your answer to decimal places.
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Ответ:
1.91 V
Explanation:
The correct cell reaction. equation is;
Br2(l) + H2(g) + 2OH-(aq) -> 2Br-(aq) + 2H2O(l)
Anode half reaction;
H2(g) + 2OH^-(aq) > 2H2O(l) +2e- -0.82 V
Cathode half reaction;
Br2(l) + 2e- > 2Br^-(aq). +1.09 V
Hence
E° cell= E°cathode - E°anode
E° cell= 1.09 - (-0.82)
E° cell= 1.91 V
Ответ:
All of them are.
Explanation: