A graduate student is working in his lab. In order to continue his experiment, he needs to calculate the total number of ions in 9.24 mol of CaBr 2 . Calculate the total number of ions in the sample.
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Ответ:
We have 9.24 moles Calcium ions and 18.48 moles bromide ions
Explanation:
Step 1: Data given
Number of moles CaBr2 = 9.24 moles
Step 2: The equation
CaBr2 →Ca^2+ + 2Br-
Step 3: Calculate number of moles
For 1 mol CaBr2 we have 1 mol Calcium ions and 2 moles Bromide ions
For 9.24 moles we have 1* 9.24 = 9.24 moles Calcium ions
For 9.24 moles we have 2-9.24 = 18.48 moles bromide ions
For 9.24 moles Ca^2+ we have 9.24 *6.022*10^23 =5.56*10^24 Calcium ions
For 18.48 moles Br- we have 1.1 * 10^25 bromide ions
Ответ:
1.67×10²⁵ ions in 9.24 moles of CaBr₂
Explanation:
First of all, we need to dissociate our compound:
CaBr₂ → Ca²⁺ + 2Br⁻
This equation means, that 1 mol of calcium bromide dissociates in 3 moles of ions (1 mol of Ca²⁺ and 2 moles of bromide, Br⁻)
Let's make a rule of three:
In 1 mol of bromide we have 3 moles of ions
Then, in 9.24 moles of bromide we must have (9.24 . 3) /1 = 27.72 moles
Let's count the ions: 27.72 mol . 6.02×10²³ ions / 1mol = 1.67×10²⁵ ions
Ответ: