A sample in the laboratory is found to contain 3.36 grams of hydrogen, 20.00 grams of carbon, and 26.64 grams of oxygen. The molecular mass is 180.156 g/mol. Determine both the empirical formula and the molecular formula.
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Ответ:
Empirical formula is CH₂O.
Molecular formula = C₆H₁₂O₆
Explanation:
Given data:
Mass of hydrogen = 3.36 g
Mass of carbon = 20.00 g
Mass of oxygen = 26.64 g
Molar mass of compound = 180.156 g/mol
Empirical formula = ?
Molecular formula = ?
Solution:
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number
Number of gram atoms of H = 3.36 / 1.01 = 3.3
Number of gram atoms of O = 26.64 / 16 = 1.7
Number of gram atoms of C = 20 / 12 = 1.7
Atomic ratio:
C : H : O
1.7/1.7 : 3.3/1.7 : 1.7/1.7
1 : 2 : 1
C : H : O = 1 : 2 : 1
Empirical formula is CH₂O.
Molecular formula:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = CH₂O = 12×1 + 2× + 16
Empirical formula mass = 30
n = 180.156 / 30
n = 6
Molecular formula = n (empirical formula)
Molecular formula = 6 (CH₂O)
Molecular formula = C₆H₁₂O₆
Ответ: