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BlueWaaaazzzBerry
27.10.2020 •
Chemistry
A sample of Ar gas has a pressure of 1.20 atm at 125°C and a volume of 1.00 L. What would the temperature be (°C) with a pressure of 1.80 atm and constant volume?
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Ответ:
597K
Explanation:
Given parameters:
Initial pressure = 1.2atm
Initial temperature = 125°C = 125 + 273 = 398K
Initial volume = 1.00L
Final pressure = 1.80atm
Final volume = 1.00L
Unknown:
Final temperature = ?
Solution:
To solve this problem, we must understand that at constant volume, the pressure of a given mass of gas varies directly with the absolute temperature.
Mathematically;
where P and T are the pressures
1 and 2 are the initial and final states
Now insert the parameters and solve;
T₂ x 1.2 = 398 x 1.8
T₂ = 597K
Ответ:
bml all lives matter but durning this timeblack lifes matter the most
Explanation: