thegreentnt5025
14.03.2020 •
Chemistry
A sample of gas has a volume of 1.20 L at standard conditions. Find its volume at 35.0 oC and 900 torr. (R = 62.4 L torr/K *mol)
Group of answer choices
A. 1.14 L
B. 2.52 L
C. 0.980 mL
D. 3.92 mL
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Ответ:
Option A. 1.14L
Explanation:
Data obtained from the question include:
V1 = 1.20 L
P1 = at stp = 760torr
T1 = at stp = 273K
P2 = 900torr
T2 = 35°C = 35 + 273 = 308K
V2 =?
Using P1V1/T1 = P2V2/T2, we can obtain the new volume as follows:
P1V1/T1 = P2V2/T2
(760 x 1.2)/273 = (900 x V2) /308
Cross multiply to express in linear form
273 x 900 x V2 = 760 x 1.2 x 308
Divide both side by 273 x 900
V2 = (760 x 1.2 x 308) /(273 x 900)
V2 = 1.14L
Ответ:
what rosemary said
Explanation:
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