A sample of oxygen gas has a volume of 150 mL when its pressure is 0.587 atm at 155 K. If the pressure and temperature are increased to STP, what will the new gas volume be?

V₂ = 155.17 mL

Explanation:

Given data:

Initial volume = 150 mL

Initial pressure = 0.587 atm

Initial temperature = 155 K

Final temperature = 273.15 K

Final volume = ?

Final pressure = 1 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 0.587 atm × 150 mL × 273.15 K / 155 K × 1 atm

V₂ = 24050.86 atm .mL. K / 155 K.atm

V₂ = 155.17 mL