A scientist needs 1/3 liter of hydrochloric acid to perform an experiment. She has 2/3 liter of sulfuric acid. she has 7/12 liter more sulfuric acid than hydrochloric acid.
Solved
Show answers
More tips
- F Family and Home How to Remove Fading from Clothes: Tips and Tricks...
- F Family and Home How to Remove Tar Stains: Tips and Recommendations from Experts...
- L Leisure and Entertainment How to Learn to Draw Graffiti: Tips for Beginners...
- G Goods and services How to sew a ribbon: Tips for beginners...
- L Leisure and Entertainment How to Land on the Moon: Your Comprehensive Guide...
- H Health and Medicine Novomin: What is it and how to use it?...
- A Art and Culture Attention, the Final Episode of Margo is Almost Here!...
- A Art and Culture How to Learn Screaming: Step-by-Step Guide for Beginners...
- D Dating, Love, Relationships 10 Useful Tips on How to Survive a Breakup?...
- S Style and Beauty How to Break in New Shoes: 7 Simple Methods...
Answers on questions: Chemistry
- C Chemistry What is system input? a. feedback from scientists about the results of a system b. the ordered processes that the system uses to change raw material c. material that has been...
- H History The Colonists were put into a difficult position financially, as was A. England B. Spain C. Colonist...
- E English Which evidence best supports the claim that montresor is insane? a. he wears a strange costume. b. thoughts of fortunato’s death make him smile. c. he pays full price for...
- M Mathematics Which property justifies step 1? given: 4(x ? 6) + 12 = 20 step 1: 4x ? 24 + 12 = 20 step 2: 4x ? 12 = 20 step 3: 4x = 32 step 4: x = 8 a) identity property b) distributive...
- C Computers and Technology Compare volatile and nonvolatile devices. which one would be better for long-term data storage? volatile, because it can only be accessed by those with a password volatile,...
Ответ:
Grams of Chromium(III) nitrate produced : 268.95 g
Further explanationGiven
0.85 moles of Lead(IV) nitrate
Required
grams of Chromium(III) nitrate
Solution
Reaction
Balanced equation :
2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb
From the equation, mol ratio of Pb(NO₃)₄ : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃
mol Cr(NO₃)₃ =
Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :
mass = mol x MW
mass = 1.13 x 238.0108
mass = 268.95 g